Therefore, the smallest number which when diminished by 7, is divisible 12, 16, 18, 21 and 28 is 1015.

What is the least number which when decreased by 7 is divisible by each one of 15 21 30?

Step-by-step explanation:

So the required number is 1015.

What is the least number which when increased by 7 is divisible by each one of 24 32 36 54?

Explanation: Required number = (L.C.M. of 24, 32, 36, 54) - 5 = 864 - 5 = 859. The least multiple of 7, which leaves a remainder of 4, when divided by 6, 9, 15 and 18 is : A.

What is the smallest number which when decreased by 8?

So we add 8 in the LCM of the numbers. i.e. 10395+8=10403. Therefore, The required number which when decreased by 8 is divisible by 21, 27, 33, and 55 is 10403.

What is the smallest number which when decreased by 3?

• L.C.M. of 18, 36, 32 and 27.
• = 2 × 2 × 3 × 3 × 3 × 8 = 864.
• ∴ required number = 864 + 3 = 867.

Find the smallest number which when diminished by 7, is divisible by 12, 16, 18, 21 and 28

What is the least number which when decreased by 9 is divisible by each of the numbers 72 96 and 160?

2520 is the lowest.

What is the least number which when diminished by 7?

We are given that the smallest number is diminished by 7, to get divisible by all the numbers. ⇒ Required Number −7= LCM of all the numbers. Therefore, the smallest number which when diminished by 7, is divisible 12, 16, 18, 21 and 28 is 1015. Thus, option (B) is the correct answer.

What is the least number which when divided by 12 20 and 24 leaves in each case a remainder of 8?

The least number, which when divided by 12, 15, 20 and 54 leaves in each case a remainder of 8 is: [A]. = 548.

What is the least number of 4 digits when increased by 7 divisible by 35 48 and 56?

(35, 48, 56) = 7 × 8 × 5 × 6 = 1680. Also, 1680 - 7 = 1673. Thus, the required four digit number is 1673.

What is the smallest number which when divided by 7 18 56 and 36?

Answer is "504"

How do you solve for LCM?

One way to find the least common multiple of two numbers is to first list the prime factors of each number. Then multiply each factor the greatest number of times it occurs in either number. If the same factor occurs more than once in both numbers, you multiply the factor the greatest number of times it occurs.

What is the smallest number which when diminished by 3 is divisible by 21 28 36 and 45?

=1263. When we take LCM for 21,28,36,45 and added to 3.

In which of the following numbers is the place value of 7 highest?

→ tenths > hundredths > thousandths . therefore we can conclude that, 0. 7 (option 1) had the highest place value of 7 .

What is the remainder if 8 25 is divided by 7?

We need to find the remainder of (8 power 25) divided by 7 is 1. If 8 is divided by 7, then the remainder is 1. Therefore, the remainder of (8 power 25) divided by 7 is 1.

What is the four digit number which when divided by 12 15 and 21 leaves remainder 7 in each case?

To find the largest 4 digit number which, when divided by 12, 15 and 21, leaves remainder 7, we have to divide the 9999 by 420 and add 7 after subtracting the remainder from 9999. When we divide the 9999 by 420, the remainder is 339.

What is the least number when divided by 12 15 20 and 54 leaves 4 as remainder in each case?

Answer: LCM of 12, 15, 20, and 54 is 540. Explanation: The LCM of four non-zero integers, a(12), b(15), c(20), and d(54), is the smallest positive integer m(540) that is divisible by a(12), b(15), c(20), and d(54) without any remainder.

What is the least number which when divided by 5 6 7 and 8 leaves a remainder 3?

Hence 1683 is the least number which when divided by 5, 6, 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder.

What is the least natural number which when divided by 8 12 15 or 16 leaves a remainder of 7?

So the ans. is 147.

What is the least number which when divided by 15 36 and 40 leaves 7 as remainder?

So, 11935 is the required number.

What is the smallest number of 7 and 12?

The LCM of 7 and 12 is 84. To find the least common multiple (LCM) of 7 and 12, we need to find the multiples of 7 and 12 (multiples of 7 = 7, 14, 21, 28 . . . . 84; multiples of 12 = 12, 24, 36, 48 . . . . 84) and choose the smallest multiple that is exactly divisible by 7 and 12, i.e., 84.

What is the least number of 4/6 and 8?

The LCM of 4, 6, and 8 is the product of all prime numbers on the left, i.e. LCM(4, 6, 8) by division method = 2 × 2 × 2 × 3 = 24.

Which is the smallest number which when lessened by 5 is exactly divisible by 36 48 24 and 72?

1013 is the smallest number!!!

What is the lowest number which is less by 5 to be divided by 16 24 and 36 exactly?

Ans. =10368 is the smallest 5 digit no. exactly divisible by 16,24,36 and 54. First find the LCM of 16,24,36 and 54.

Which is the smallest number which on being decreased by 3 is completely divisible by 18 36 32 and 27?

Prime factorize all the given numbers. Hence, if we decrease 867 by 3, 864 will be divisible by all 18, 36, 32 and 27.